In IF7 molecule the central atom is I. Seven atomic orbitals (one s, three p and three d orbitals) hybridize to form seven sp3d3 hybrid orbitals. These are singly filled. These hybrid orbitals overlap with singly filled 2pz atomic orbitals of seven F-atoms to form seven I-F sigma bond.

Does IF7 have sp3d hybridization?

So here option D is correct. Note : We know that the number of valence electron in central metal atom Iodine is seven and in fluorine it is also seven so total number of valence electron in molecule is $7 + 7 times 7 = 56$. Hence it need seven atomic orbital so possess $s{p^3}{d^3}$ hybridization.

What is the geometry and shape of IF7?

In IF7, Iodine is sp3d3 hybridised with 7 bond pairs and zero lone pairs and has pentagonal bipyramidal shape.

How many sigma bonds are in IF7?

But, the formation of only 6 σ bonds can happen between an iodine and 6 fluorine atoms, as σ bonds involve head-on overlap of orbitals, and there are only 6 orbitals capable of doing that (the s and p orbitals, and the two ‘axial’ d-orbitals).

Which molecule has sp3d hybridization?

Hence, SF4 has sp3d hybridization.

What is the Lewis structure of IF7?

Iodine heptafluoride, also known as iodine(VII) fluoride or iodine fluoride, is an interhalogen compound with the chemical formula IF7. It has an unusual pentagonal bipyramidal structure, as predicted by VSEPR theory.

Are all bonds in IF7 equal?

Iodine retains a lone pair and the overall geometry of the molecule is polar. The resulting molecules are more strongly attracted to one another than IF7 molecules are. IF7 are nonpolar (their shape is complex, but the dipole moment is zero or close to it).

Does IF7 have coordinate bond?

As per the VSEPR Theory, the structure of IF7 is pentagonal bipyramidal and its hybridisation is sp3d3, since its coordination number is 7. Thanks.

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